Question

.The base and hypotenuse of a right triangle are respectively 5cm and 13cm long. Its area is​

Answer 1

$given \\ \\ b = 5 \: \: \: \: \: \: hypt = 13 \\ \\ to \: \: \: find \: \: = area \\ \\ solution = \\ \\ {hypt}^{2} = {b}^{2} + {h}^{2} \\ \\ {13}^{2} = {5}^{2} + {h}^{2} \\ \\ 169 = 25 + {h}^{2} \\ \\ 169 - 25 = {h}^{2} \\ \\ 144 = {h}^{2} \\ \\ h = 12cm \: \: \\ \\ area = \frac{1}{2} \times b \times h \\ \\ area = \frac{1}{2} \times 5 \times 12 \\ \\ area = 5 \times 6 \\ \\ area = 30 {cm}^{2}$

Answer 2

Answer:

$\begin{gathered}given \\ \\ b = 5 \: \: \: \: \: \: hypt = 13 \\ \\ to \: \: \: find \: \: = area \\ \\ solution = \\ \\ {hypt}^{2} = {b}^{2} + {h}^{2} \\ \\ {13}^{2} = {5}^{2} + {h}^{2} \\ \\ 169 = 25 + {h}^{2} \\ \\ 169 - 25 = {h}^{2} \\ \\ 144 = {h}^{2} \\ \\ h = 12cm \: \: \\ \\ area = \frac{1}{2} \times b \times h \\ \\ area = \frac{1}{2} \times 5 \times 12 \\ \\ area = 5 \times 6 \\ \\ area = 30 {cm}^{2} \end{gathered}givenb=5hypt=13tofind=areasolution=hypt2=b2+h2132=52+h2169=25+h2169−25=h2144=h2h=12cmarea=21×b×harea=21×5×12area=5×6area=30cm2$

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