Question

The base and hyptenuse pf a right angled triangle are 12 cm and 20 cm . Find ots perimeter amd area

Answer 1

Answer:

we know that the square of the longest side is equal to the sum of square of other two sides

let the height of the given triangle be X

=x^2=20^2-12^2

=x^2=400-144

=x^2=256

=X=√256

=X=16

now height=16, base=12

area of triangle=1/2*base*height

=1/2*12*16

=96cm^2

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