Question

The base and the altitude of a parallelogram are in the ratio 3:2findthe measure of the base and altitude if the area of the parallelogram is 3750m

Answer 1

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• base=75m
• altitude=50m

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base:altitude=3:2

so,let base be 3x and the altitude be 2x

now, area of llgm=3750 m square

base×altitude= 3750

3x × 2x = 3750

6x² = 3750

x² = 625

x=25

thus altitude → 2x = 2×25 = 50m

and base→ 3x = 3×25 = 75m

Answer 2

Question says that,

Ratio of base and altitude of a parallelogram 3 : 2

Area = 3750m²

Find the base and the altitude.

Suppose the base is $3x$ and the height is $2x$.

We know that,

Area of a parallelogram : $b \times a$

Where,

• $b$(base) = $3x$
• $a$(altitude) = $2x$

So, we can say that,

$\implies 3x \times 2x = 3750m^2$

Solving for $x$ :

$\implies 6x^2 = 3750$

$\implies x^2 = \dfrac{3750}{6}$

$\implies x^2 = 625$

$\implies x = \sqrt{625}$

$\implies x = 25$

${\therefore{\underline{\sf{The \: value \: of \: \boldsymbol{x} \: is \: 25units}}}}$

Hence,

The base is : $3x$ = 3(25) = 75m.

And altitude : $2x$ = 2(25) = 50m