the base and the altitude of a triangle are (3x -4y) and (6x +5y ) respectively .find its area
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Answered by
67
area of triangle = 1/2×base × height
=1/2 ×(3x-4y)(6x+5y)
=1/2 × 18x^2 +15xy -24yx -20y^2
=1/2×18x^2-9xy-20y^2
=18x^2-9xy-20y^2 / 2
=1/2 ×(3x-4y)(6x+5y)
=1/2 × 18x^2 +15xy -24yx -20y^2
=1/2×18x^2-9xy-20y^2
=18x^2-9xy-20y^2 / 2
monikar:
sorry
Answered by
32
The solution is:
(3x-4y) (6x+5y)
18x2 + 15xy - 24 xy - 20y2
18x2 - 9xy - 20y2
(3x-4y) (6x+5y)
18x2 + 15xy - 24 xy - 20y2
18x2 - 9xy - 20y2
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