Question

The base and the height of a parallelogram are in the ratio 1:3. Its area is 12 sq. cm. Find the base
and height.
The floor of​

Answer 1

$let \: \: base \: \: = x \: \: \: \: \: and \: \: height = 3x \\ area \: \: of \: \: parallagram = b \times h \\ = > x \times 3x = 12 \\ = > 3 {x}^{2} = 12 \\ = > {x}^{2} = \frac{12}{3} \\ = > {x}^{2} = 4 \\ = > x = \sqrt{4} = 2 \: cm$

base of parallelogram = 2 cm

and height of parallelogram = 2 × 3 = 6 cm

Answer 2

The base and the height of a parallelogram are in the ratio 1:3.

Let base be x cm.

So, height = 3x cm.

Area = 12 cm²

According to condition,

x×3x = 12

or, 3x² = 12

or, x² = 12/3

or, x² = 4

or, x = √4

or, x = 2

So, base = x cm = 2 cm.

Height = 3x cm = (3×2) cm = 6 cm.

Hence, it's base and height are 2 cm and 6 cm respectively.