the base and the height of a right angle triangle are in the ratio of 3 : 4 and its perimeter is 600 CM square find the lengths of base and height
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the perimeter cannot be in square(600 cm square)
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Let the base and height of the triangle be 3x and 4x respectively.
(Hypotenuse^2) = (3x^2) + (4x^2)
=> (Hypotenuse^2) = (25x^2)
=> (Hypotenuse) = 5x
Now,
3x + 4x + 5x = 600
=> 12x = 600
=> x = 50 cm
Therefore,
Base = 3 × 50 = 150
&
Height = 4 × 50 = 200
Hope it helps you....
(Hypotenuse^2) = (3x^2) + (4x^2)
=> (Hypotenuse^2) = (25x^2)
=> (Hypotenuse) = 5x
Now,
3x + 4x + 5x = 600
=> 12x = 600
=> x = 50 cm
Therefore,
Base = 3 × 50 = 150
&
Height = 4 × 50 = 200
Hope it helps you....
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