Question

The base and the height of a triangular field are in the ration 3 : 1. If the cost of cultivating the field at 0.80 per m² is rs. 7680, find the base and height of the field.
please solve it is urgent please i​

Answer 1

Answer:

Step-by-step explanation:

Let the height be x

then base =3x

since, area=Total cost of cultivating the field /Rate per unit

=181250/300=604.16m

A/Q=1/2*base*height=604.16

1/2*3x*x=604.16

3x*x=604.16*2/1

3x

Answer 2

Answer :-

• Base of Triangular Field = 240 m
• Height of Triangular Field = 80 m

Given :-

• Ratio of Base & Height = 3 : 1
• Rate of Cultivating Field = 0.80 / m²
• Total Cost of Cultivating Field = 7680 Rs

To Find :-

• Base of Triangular Field = ?
• Height of Triangular Field = ?

Explanation :-

Let the Base and Height of Field to be '3x' & '1x' Respectively.

As above given, we have to find the Base & Height of Triangular Field and we have the Rate of cultivating and Total cost of Cultivating.

Hence, we will use Area of Triangle Formulae

$\purple { \boxed { \bf \bigstar \: Area \: of \: Triangle \times Rate = Total \: Cost \: \bigstar }}$

$\rm : \: \implies \dfrac{1}{2} \times 3x \times 1x \times 0.80 = 7680 \: m^2$

$\rm : \: \implies 3x \times 1x \times 0.80 = 7680 \times 2 \: m^2$

$\rm : \: \implies 3x^2 \times 0.80 = 15360 \: m^2$

$\rm : \: \implies x^2 = \dfrac{15360}{0.80 \times 3} \: m^2$

$\rm : \: \implies x^2 = 6400 \: m^2$

$\rm : \: \implies x = \sqrt{6400} \: m$

$\bf : \: \implies x = 80 \: m \quad \star$

Now, Substituting the value of 'x'

$\rm \odot \: Base = 3x = 3(80) = \red{\bold{240 \; m}$

$\rm \odot \: Base = 1x = 1(80) = \red{\bold{80 \; m}$

Hence, the Base & Height of the Triangular field are 240 m and 80 m respectively.