the base and the hypotenuse of a right angled triangle are 12 cm and 20 cm. find its perimeter and area.
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In ΔABC,
(AC)² = (AB)²+(BC)² (Pythagoras theorem)
(20)² = (12)²+(BC)²
(BC)² = 400-144
BC = √256
BC = 16 cm
Perimeter = (12+16+20) cm
= 48 cm
Area of ΔABC = 1/2*b*h
= (1/2*12*16) cm²
= 96 cm²
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