Question

The base and the of the triangle are in the ratio 7:4. If the area of the triangle is 87.5 cm square.Find the base and height.

Answer 1

Answer:

AS WE KNOW AREA OF TRIANGLE IS 1/2*B*H

GIVEN: BASE =7 and HEIGHT= 4 IN RATIO

LET THESE RATIO IN A VARIABLE X

SO BASE AND HEIGHT WOULD BE 7x AND 4x RESPECTIVILY

NOW PUTTING VALUES TO EQUATION

1/2 *7x*4x = 87.5

here x =87.5*2/7*4. as when we divide

now. x= 12.5*2/4 7 it gives q as 12.5

now the. x = 25/4. as. 12.5 *2 it gives 25

now. x= 6.25

now x= 6.25 so

base = 7*6.25 and height =4*6.25

hence required answer will be after multiplying

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Answer 2

Answer:

Base = 17.5cm

Height = 10cm

Step-by-step explanation:

$࿐ \large\bf{Correct \: Question}$

1. The base and height of the triangle are in the ratio 7:4. If the area of the triangle is 87.5 cm².Find the base and height.

$࿐ \large\bf{Given}$

• Ratio of base and height = 7 : 4
• Area of the triangle = 87.5cm²

$࿐\large\bf{To \: Find}$

• Base and height of the triangle

$࿐ \large\bf{Assuming}$

• Let the base 7x cm and height 4x cm

$࿐ \large\bf{Solution}$

$✭\small\bf{Area \: = \frac{1}{2} \times Base × Height}$

$➻ \small\rm{(\frac{1}{2} \times 7x \times 4x) {cm}^{2} }$

$➻ \small\rm (14 {x) ^{2} }{cm}^{2}$

$\small \rm{14 {x}^{2} = 87.5 }$

$➻ \: \small \rm{{x}^{2} = \frac{87.5}{14} = 6.25}$

$➻ \small\rm{ \: x = \sqrt{6.25} = 2.5 }$

Base = 7xcm

= (7 × 2.5) cm = 17.5cm

Height = 4x cm

= (4 × 2.5)cm = 10cm

Hence, Base = 17.5cm and Height = 10cm