Math, asked by amrit7445, 4 months ago

The base angle of an isosceles triangle is 15 ° more than its vertical angle. find its each angle

40°40°,100°

65°,65°,50°

45°,45°,90°​

Answers

Answered by bagkakali
0

Answer:

let the vertical angle is x°

In an isoscele triangle the two base angles are equal.

so each base angles are =(x+15)°

sum of the angles of a triangle is 180°

so,

x+x+15+x+15=180

=> 3x=180-30=150

=> x=150/3=50

so, vertical angle is 50° and each base angle is

(50+15)°=65°

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