The base angle of an isosceles triangle is 15 ° more than its vertical angle. find its each angle
40°40°,100°
65°,65°,50°
45°,45°,90°
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Answer:
let the vertical angle is x°
In an isoscele triangle the two base angles are equal.
so each base angles are =(x+15)°
sum of the angles of a triangle is 180°
so,
x+x+15+x+15=180
=> 3x=180-30=150
=> x=150/3=50
so, vertical angle is 50° and each base angle is
(50+15)°=65°
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