Question

the base angle of an isosceles triangle is 15 degree more than the vertex angle find its each angle

Answer 1

Answer:

Answer:

Base1 =65 degrees,

Base2 = 65 degrees

Vertical angle = 50 degrees

Step-by-step explanation:

Let the vertical angle = x

Then, Base1 angle = x+15

Base2 angle = x+15

Now,

Sum of angles of triangle = 180

x + x+15 + x+ 15 = 180

3x + 30 = 180

3x = 180 - 30

3x = 150

x = 150/3

x = 50

Hence,

Vertical angle = x = 50

Base1 angle = x +15 = 50+15 = 65

Base2 angle = x + 15 = 50 +15 =65

Answer 2

Answer:

50,65,65

Step-by-step explanation:

let the vertex angle be x

therefore the other 2 angles will be x+15 (in a iscosceles ∆ 2 angles r equal)

also we know the sum of interior angles is 180 degrees

therefore adding all the quations

x+x+15+x+15=180

3x+30=180

3x=150

x= 50

Hope this helps !

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