Question

the base angle of an isosceles triangle is 20 more than thrice the vertex angle. find the equal angles

Answer 1

Step-by-step explanation:

Lets vertix angle= x

As per condition

First Isoscele angle= 3x+20

Second Isoscele angle= 3x+20

We know that

sum of triangles = 180

x + (3x+20) + (3x+20) = 180

7x+40 = 180

7x = 180 - 40

7x = 140

x = 140÷7

x = 20

So vertex angle = 20

First Isosceles angle = 3×20+2

= 60+20

=80

Second Isoscele angle = 80

we hope must satisfy with answer

Answer 2

Answer:

Step-by-step explanation:

Lets vertex angle= x

So As per condition

First Isoscele angle= 3x+20

Second Isoscele angle= 3x+20

We know that

So we have two angle we need one more angle so we take them as x

Angle sum of triangles is = 180

x + (3x+20) + (3x+20) = 180

7x+40 = 180

7x = 180 - 40

7x = 140

x = 140÷7

x = 20

So vertex angle = 20

First Isosceles angle = 3×20+2

= 60+20

=80

Second Isoscele angle = 80

we hope must satisfy with answer

Read more on Brainly.in - https://brainly.in/question/12873072#readmore