Question

the base angle of an isosceles triangle is 24°more than the vertical angle. Find the measure of each angel​

Answer 1

Answer:

$2x + 24 { {}^{0 } }^{} = 180 {}^{0 } \\ 2x = 180 - 24 \\ 2x = 156 {}^{0} \\ x = 156 \div 2 \\ x = 78 \\ 78 + 24 = 102 {}^{0 } \\ therefore102 \: 39 \: 39degress$

Answer 2

Step-by-step explanation:

Question :-

• the base angle of an isosceles triangle is 24°more than the vertical angle. Find the measure of each angel

To find :-

• Find the measure of each angel

Solution :-

• Let the angle be 2x

$→ 2x + 24° = 180°$

$→ 2x = 180° - 24°$

$→ 2x = 156°$

$→ x = 156 \div 2 \: or \: \frac{156}{2}$

$→ x = 78°$

$→ 78 + 24 = 102°$

$→ 78 \div 2 = 39$

Answer :- 102° , 39° and 39° .