Question

the base angles of an isosceles triangle are m 15° more than it's third angle.find the measures of all angles​

Answer 1

Let vertical angle of the isosceles triangle = x°

∴ Each base angle = x + 15°

X + 15° + x + 15° + x° = 180°

(Sum of angles of a triangle)

⇒ 3x + 30° = 180°

⇒ 3x = 180° - 30° = 150°

∴ x = 150°/3 = 50°

Hence vertical angle = 50°

and each base angle = 50° + 15° = 65°

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