Math, asked by avpatil31, 4 months ago

the base area of cylinder is 20 square cm and the height is 5 cm.what is the volume of cylinder​

Answers

Answered by Anonymous
30

Given

  • Base area of Cylinder = 20 cm²
  • Height of Cylinder = 5 cm

Explanation:

✮Firstly We've to find the Radius of the Volume using formula of area of Circle as the Base of the Cylinder is in Circular Shape:-

 \dag {\pink{\boxed{\underline{\sf{ Area_{(Circle )} = πr^2 }}}}} \\ \\ \colon\implies{\sf{ 20 = \dfrac{22}{7} \times (r)^2 }} \\ \\ \\ \colon\implies{\sf{ \dfrac{140}{22} = (r)^2 }} \\ \\ \\ \colon\implies{\sf{ r^2 = 6.36 }} \\ \\ \\ \colon\implies{\sf{ r = \sqrt{6.36} \mapsto 2.5 \ cm \ \ \ (approx.) }} \\

✮Now, we can find the Volume of the Cylinder using height and Radius of the Cylinder that we've as:-

 \dag{\pink{\boxed{\underline{\sf{ Volume_{(Cylinder)} = πr^2h }}}}} \\ \\ \\ \colon\implies{\sf{ Volume_{(Cylinder)} = \dfrac{22}{7} \times (2.5)^2 \times 5 }} \\ \\ \\ \colon\implies{\sf{ Volume_{(Cylinder)} = \dfrac{22}{7} \times 6.5 \times 5}} \\ \\ \\ \colon\implies{\sf{ Volume_{(Cylinder)} = \cancel{ \dfrac{22}{7} } \times 32.5 }} \\ \\ \\ \colon\implies{\sf{ Volume_{(Cylinder)} = 3.14 \times 32.5 }} \\ \\ \\ \colon\implies{\sf{ Volume_{(Cylinder)} = 102.05 \ cm^3 }} \\

Hence,

The Volume of the Cylinder will be 102.05 cm³.

Answered by thebrainlykapil
49

Given :

  • Base area of Cylinder = 20cm²
  • Height of Cylinder = 5cm

 \\

To Find :

  • Volume of Cylinder

 \\

Solution :

✰ As we know that, Area of Circle is πr² and Volume of Cylinder is πr²h . Now, In this question Base Area of Cylinder is given and height is also given. So we will simply apply the formula of Volume of Cylinder .

⟾ Volume of Cylinder = πr²h

⟾ Volume of Cylinder = 20 × 5

⟾ Volume of Cylinder = 100cm³

Thus Volume of Cylinder is 100cm³

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Additional Info :

Formulas Related to Cylinder :

\boxed{ \sf{Area\:of\:Base\:and\:top =\pi r^2}}  \\\boxed{ \sf{Curved \: Surface \: Area =2 \pi rh}} \\\boxed{ \sf{Total \: Surface \: Area = 2 \pi r(h + r)}} \\\boxed{ \sf{Volume=\pi r^2h}}

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