The base area of the cylinder is 100 cm^2 and the height of the cylinder is 3 cm. If the volume
of the whole solid is 500 cm^3 find the height of the solid thus formed.
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Answer:
A=πr
2
π
100
=r
2
....(1)
Put the value of eq.1 in eq 2
500=A×h
1
+
3
1
πr
2
h
2
500=100×3+
3
1
π×
π
100
×h
2
500−300=
3
100h
2
200=
3
100h
2
h
2
=6cm
H=h
1
+h
2
=3+6
=9cm
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