the base at an isoceles tringle is 12 cm & it is parimeter is 32 cm . find its area .
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ANSWER:
Let x be the equal side.
==>Perimeter:2x+12=32.
x=10cm.
Height of the base=8 (by solving using Pythagorean theorem).
Area of triangle=1/2*b*h.
Area of triangle =1/2*12*8.
Area of triangle=48cm^2.
Let x be the equal side.
==>Perimeter:2x+12=32.
x=10cm.
Height of the base=8 (by solving using Pythagorean theorem).
Area of triangle=1/2*b*h.
Area of triangle =1/2*12*8.
Area of triangle=48cm^2.
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area of isosceles triangle= perimeter/base
=32/12
=8/3
=32/12
=8/3
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