Question

the base BC of an isosceles triangle ABC is 16 cm and each of the equal side is 10 cm its area will be​

Answer 1

Answer:

Step-by-step explanation:

Equal sides of the isosceles triangle = 10cm

Base = 16cm

Let's use herons formula to find the area.

Area = √s (s - a) (s - b) (s - c)

Where,

a = 10cm

b = 10cm

c = 16cm

To find s:-

s = a+b+c/2

s = 10 + 10 + 16/2

s = 36/2

s = 18

Area = √s (s - a) (s - b) (s - c)

Area = √18 (18 - 10) (18 - 10) (18 - 16)

Area = √18 × 8 × 8 × 2

Area = √3 × 3 × 2 × 8 × 8 × 2

Area = 3 × 2 × 8

Area = 48cm^2

Answer 2

Step-by-step explanation:

let a,b,c be bc ac and ab

then s= a+b+c/2

= 16+10+10/2=36/2= 18cm

then area of the isosceles ∆= √s(s-a)(s-b)(s-c)

= √18(18-16)(18-10)(18-10)

=√18*2*8*8

=48cm^2

hope this help