Question

The base BC of an isosceles triangle ABC is 20cm, and each of its equal side is of length 26cm. Find the length of the altitude through the vertex A.

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Answer 1

Answer:

Correct option is

B

24cm

Given BC=20

AB=AC=26

The Altitude from A will divide BC into 2 equal parts

BD=CD=

2

1

20=10

Now, in △ADC which is a right Angled Triangle

AD

2

=AC

2

−CD

2

⇒AD

2

=26

2

−10

2

=676−100=576⇒AD=

576

=24

Answer 2

Answer:

Given BC=20AB=AC=26

The Altitude from A will divide BC into 2 equal parts

BD=CD=2120=10

Now, in △ADC which is a right Angled Triangle 

AD2=AC2−CD2⇒AD2=262−102=676−100=576⇒AD=576=24