the base BC of triangle ABC is divided at D, so that BD= 1/2 DC . prove that area of triangle ABD = 1/3 are of triangle ABC
Answers
Answered by
3
GIVEN: BD = 1/2 DC
CONST: Draw a line ⊥ BC, AE ⊥ BC
Let AE = h (Ht. of ΔABC)
∵ BD + DC = BC
BD + 2BD = BC
3BD = BC
BD = 1/3 BC
Ar. ΔABD = 12 × BD × AE = 1/2 × (1/3 BC) × AE
= 13 × 12 = BC × AE
= 13 × Ar. ABC
Hope I helped you! :)
CONST: Draw a line ⊥ BC, AE ⊥ BC
Let AE = h (Ht. of ΔABC)
∵ BD + DC = BC
BD + 2BD = BC
3BD = BC
BD = 1/3 BC
Ar. ΔABD = 12 × BD × AE = 1/2 × (1/3 BC) × AE
= 13 × 12 = BC × AE
= 13 × Ar. ABC
Hope I helped you! :)
manyasaraswat22:
Thank you
Hi
hii
Similar questions