Question

The base diameter of a closed cylinder is 3.6 cm and height is 8.2 cm, then find its total surface area. (???? = 3.14)

Answer 1

$tsa = 2\pi \: r \: ({h + r}) \\ \: \: \: \: \: \: 2 \times 3.14 \times 1.3 \times (8.2 + 1.3) \\ \: \: \: \: 77.558 {cm}^{2}$

Answer 2

Answer:

$113.04 cm^2$

Step-by-step explanation:

Diameter of cylinder = 3.6 cm

Radius of cylinder = $\frac{Diameter}{2}=\frac{3.6}{2}=1.8$

Height of cylinder = 8.2 cm

Total surface area of cylinder =$2 \pi r h + 2 \pi r^2$

                                                  =$2 \times 3.14 \times 1.8 \times 8.2+ 2 \times 3.14 \times 1.8^2$

                                                  =$113.04 cm^2$

Hence its total surface area is $113.04 cm^2$