Question

The base f a parallelofram is thrice its height. if its area is 768 cm square, find the base and height of the parallelogram

Answer 1

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Answer 2

$\underline{\underline{\mathfrak{\Large{Solution : }}}} \\ \\ \\ \underline {\sf {Given,}} \\ \\ \\ \sf\: Let\: \: height\: \: be\: \: 'x' \\ \\ \\ \sf\: So, \: Base = 3x \\ \\ \\ \underline {\sf {To\: Find :}} \\ \\ \\ \sf\: height\: and\:base\:of\:Parallelogram \\ \\ \\ \underline {\sf {Procedure :}} \\ \\ \\ \large{\boxed{\sf {\:Area\:of\:Parallelogram = base \:×\: height}}} \\ \\ \\ \sf\implies\: 768 \:= \: 3x \: \cdot \:x \\ \\ \\ \sf\implies\: 768 \: = \: 3x^2 \\ \\ \\ \sf\implies\: x^2 = \dfrac {768}{3} \\ \\ \\ \sf\implies\: x^2 \: = \: 256 \\ \\ \\ \qquad\large {\boxed {\sf {x = 16}}} \\ \\ \\ \sf\: height\: of\:Parallelogram = 16 \:cm\\ \\ \\ \sf\: Base\:of\:Parallelogram = 3 × 16 = 18 cm$