Question

the base of a cylindrical vessel is 300 cm² . water is poured up to the depth of 7 cm . calculate the pressure on the base ​

Answer 1

Answer:

Explanation:

[a]

Pressure = hdg

= 0.06 m × 10³ kg/m³ × 10 m/s²

= 600 Pa

Pressure exerted is 600 Pa

[b]

Thrust = Pressure × Area

= 600 Pa × 300 × 10⁻⁴ m²

= 18 N

Thrust on base is 18 N

Answer 2

$\bold{(a) \: The \: pressure} \\ \bold{Height \: = \: 6cm \: to \: m} \\ \bold{ = \: \frac{6}{100} } \\ \bold{ = \: 0.06 \: m} \\ \bold{Density \: = \: 1000 \: kgm^-3} \\ \bold{Acceleration \: due \: to \: gravity \: = \: 10ms^-2} \\ \bold \green{pressure \: = \: hpg} \\ \bold{ = \: 0.06 \: m \times 1000 \: kgm^-3 \times 10 \: ms^-2} \\ \bold \red{ = \: 600 \: Pa \: \: ....ans}$

$\bold{(b) \: The \: thrust \: of \: water \: on \: the \: base} \\ \bold{Pressure \: = \: \frac{force}{area} } \\ \bold \green{force \: = \: Pressure \times area} \\ \bold{ = \: 600 \: Pa \times 300 \: {cm}^{2} } \\ \bold \red{ = \: 18 \: N \: \: ....ans}$

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