The base of a cylindrical vessel measures 300 cm^2. Water is poured into it up to a depth of 6 cm. Calculate pressure of the water on the base in SI unit. (Take : g = 10 ms^-2, density of water = 1000 kgm^-3)
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Question :
The base of a cylindrical vessel measures 300cm². Water is poured into up to a depth of 6m. Calculate pressure of the water on the base in SI Unit. (Take : g = 10 m/s², Density of water = 1000 kg/m².)
Given :
- The base of a cylindrical vessel = 300 cm².
- Height, h = 6cm = 0.06m.
- Gravity due to acceleration, g = 10 m/s².
- Density of water, ρ = 1000 kg/m².
Solution :
We know that,
→ p = ρgh.
Where,
- P = Pressure.
- ρ = Density of water.
- g = gravity due to acceleration.
- h = height.
Now,
Put the given values in the above formula.
→ 100 × 10 × 0.06
→
→ 600 Pa.
★ The pressure of water of the base is 600 Pa.
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