Question

The base of a isosceles triangle is 4/3 the perimeter of triangle is 4 2/15cm.what is the length of either of the remaining equal sides?








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Answer 1

Given :

• Base of an isosceles triangle is 4/3.
• Perimeter = 62/15 cm.

Find :

• The equal side of an isosceles triangle.

Formula :

• Perimeter = 2a + b

Solution :

Perimeter = 2a + b

$\: \: \: \: \frac{62}{15} = 2 a + \frac{4}{3}$

$= > \frac{62}{15} - \frac{3}{4} = 2a$

$= > \frac{203}{60} = 2a$

$= > a = 1 \frac{83}{120} \: \: cm \: \: \: \: \: or \: \: \: \frac{ 203}{120} \: \: cm.$

Hence :

• The equal side is 203/120.

Answer 2

Step-by-step explanation:

The base of a isosceles triangle is 4/3 the perimeter of triangle is 4 2/15cm.what is the length of either of the remaining equal sides?