The base of a isosceles triangle is 4/3cm.The perimeter of the triangle is 4 2/15cm.What is the length of either of the remaining equal sides?
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Answer:
Let any of the remaining side of the isosceles triangle is x cm in length. Then,
Perimeter of triangle, =x+x+43=2x+43 cm
⇒2x+43=4215( Perimeter is 4215)
⇒2x+43=6215⇒2x=6215−43
⇒2x=4215⇒x=1410=75=125 cm
So, Required sides of given triangles are 125 cm each.
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Step-by-step explanation:
n hOws Ur 10 class life
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