the base of a isosceles triangle is 7/2 cm. the perimeter of the triangle is 10 cm. what is the length of either of the equal side
Answers
Answered by
4
Answer:
Let the length of equal sides be x cm.
Perimeter = x cm + x cm + Base = 10 cm
2x + 7/2 = 10
On transposing 4/3 to R.H.S, we obtain
2x = 10 - 7/2
2x = 10.2/2 - 7/2
2x = 35
On dividing both sides by 2, we obtain
2x/2 = 35/2
x = 17.5
Answered by
1
Answer:
answer is 4 6/7 cm
Step-by-step explanation:
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