Question

the base of a isosceles triangle measurrs 80 cm and its area is 360cm.find the perimeter of the triangle​

Answer 1

Answer:

Area of triangle =

2

1

×base×height=360 sq cm

2

1

×80×height=360

=> height =9 cm.

Since the height of the triangle, divides it into two right angled triangles,

a

2

=h

2

+(

2

b

)

2

=>a

2

=9

2

+(

2

80

)

2

=1681

Hence, a=41 cm.

Perimeter of the triangle = Sum of all sides = a + a + b =41+41+80=162cm

Answer 2

Answer:

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