The base of a ladder is 7 feet away from the wall. The ladder reaches 3 feet up the wall. Determine the angle formed between the ladder and the ground.
Answers
Answered by
0
The angle would be 23.2
Step-by-step explanation:
From the question, it is clear that the distance of ladder from the wall is 7 feet which is known as the base and the height of wall that the ladder has attained is 3 feet.
b= 7
p = 3
Ф = ?
So, from the trigonometric ratios, we know that
tan Ф = perpendicular/ base
tan Ф = 3/7
Ф = tan-1 (3/7)
Ф = 23.2
Answered by
1
Given:
The distance between the ladder and the wall, b = 7 feet
The height to which ladder reached on the wall, p = 3 feet
To Find:
The angle formed between the ladder and the ground.
Calculation:
- Let the angle formed between the ladder and the ground be θ.
- Then according to the question:
tan θ = p/b
⇒ θ = tan⁻¹ (p/b)
⇒ θ = tan⁻¹ (3/7)
⇒ θ = tan⁻¹ (0.4286)
⇒ θ = 23.2°
- So, the angle formed between the ladder and the ground is 23.2°.
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