Question

The base of a parallellogram is (2x+3 units)and the corresponding height is (2x-3 units).
a)write formula to find area of a paralellogram
b)find area of paralellogram in terms of x
c)compute the area of paralellogram of x=30 units?

Answer 1

= (2x+3)×(2x−3)

= (2x)

2

−3

2

= (4x

2

−9) sq units

Here, x=10

Total area= 4×10−9=400−9=391 sq units

Answer 2

Area of parallelogram = Base × Height

$</p><p>= (2x+3)×(2x−3)</p><p></p><p>= (2x) </p><p>2</p><p> −3 </p><p>2</p><p> </p><p></p><p>= (4x </p><p>2 - 9)$

Here, x=10

Total area= 4×10−9=400−9=391 sq units