Question

The base of a parallelogram is 3 times its height. If the area of the parallelogram 108cm
find the hight and base of the paralelogram​

Answer 1

Answer:

height = 6 cm,

Base = 18 cm.

Step-by-step explanation:

Given:

• Base = 3 × height
• Area of parallelogram = 108 cm²

To find:

• Height (h) = ?
• Base of parallelogram (b) = ?

Solution:

Let the height of parallelogram be 'h'.

Now we know that, Base = 3h

>> Area of parallelogram = Base × height

So, let's put the given values first.

⇒ 108 = 3h x h

⇒ 108 = 3h²

⇒ 108/3 = h²

⇒ 36 = h²

⇒ $\sf{\sqrt{36}\:=\:h}$

⇒ 6 = h

Hence, height of parallelogram = 6 cm.

Now, we knew that Base = 3 × h

So put the value of height there,

⇒ Base = 3 × 6

⇒ Base = 18

Therefore, Base = 18 cm.

Answer 2

★ Given:-

• Base of parallelogram = 3 times height

• Area of parallelogram = 108 cm²

★ To Find:-

• Height of the parallelogram

• Base of parallelogram

★ Formula Used:-

• Area of parallelogram = Base × Height

★ Solution:-

Let the height of parallelogram be x

The base of parallelogram be 3 × x = 3x

➥ According to given conditions;

Area of parallelogram = 108cm²

➟ Base × Height = 108cm²

➥ Putting the assume value in equation:

➟ 3x × x = 108cm²

➟ 3x² = 108cm²

➟ x² = 108 ÷ 3

➟ x² = 36

➟ x = √36

➟ x = √6×6

∴ x = 6cm

★ Answer:-

• Height of the parallelogram = x = 6cm

• Base of parallelogram = 3x = 18cm