Question

the base of a parallelogram is 8 cm and it's height is 7 cm, then its area is ______.

(a) 28 sq. cm.

(b) 42 sq. cm.

(c) 56 sq. cm.

(d) 70 sq. cm.​

Answer 1

Given : The base of a parallelogram is 8 cm and it's height is 7 cm .

Need To Find : The Area of Parallelogram.

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⠀⠀⠀⠀⠀Finding Area of Parallelogram :

$\dag\:\cal{As,\:We\:know\:that\::}$

$\qquad \quad \dag\:\:\bigg\lgroup \sf { Area _{(Parallelogram)} = b \times h }\bigg\rgroup$

⠀⠀⠀⠀Here b is the Base of Parallelogram & h is the Height of Parallelogram. ⠀⠀⠀

$\qquad \longmapsto \sf{Area = 8 \times 7 }$

$\qquad \longmapsto \cal{\purple {\underline { Area = 56\:cm^2 }}}$

Therefore,

⠀⠀⠀⠀⠀$\therefore {\underline{ \mathrm {  Area \:of\:Parallelogram \:is\:\bf{56\: cm^2}}}}$

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$\large {\boxed{\sf{\mid{\overline {\underline {\star More\:To\:know\::}}}\mid}}}$

• $\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}$

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Answer 2

Area of Parallelogram = Base * Height

Area = 8 * 7

Area = 56 cm²