Math, asked by taibanishams, 2 months ago

the base of a parallelogram is 8 cm and it's height is 7 cm, then its area is ______.

(a) 28 sq. cm.

(b) 42 sq. cm.

(c) 56 sq. cm.

(d) 70 sq. cm.​

Answers

Answered by BrainlyRish
3

Given : The base of a parallelogram is 8 cm and it's height is 7 cm .

Need To Find : The Area of Parallelogram.

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⠀⠀⠀⠀⠀Finding Area of Parallelogram :

\dag\:\cal{As,\:We\:know\:that\::}\\\\

\qquad \quad \dag\:\:\bigg\lgroup \sf { Area _{(Parallelogram)} = b \times h  }\bigg\rgroup

⠀⠀⠀⠀Here b is the Base of Parallelogram & h is the Height of Parallelogram. ⠀⠀⠀

\qquad \longmapsto \sf{Area = 8 \times 7  }\\

\qquad  \longmapsto \cal{\purple {\underline { Area = 56\:cm^2 }}}\\

Therefore,

⠀⠀⠀⠀⠀\therefore {\underline{ \mathrm {  Area \:of\:Parallelogram \:is\:\bf{56\: cm^2}}}}\\

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\large {\boxed{\sf{\mid{\overline {\underline {\star More\:To\:know\::}}}\mid}}}\\\\

  • \begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}

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Answered by Anonymous
0

Area of Parallelogram = Base * Height

Area = 8 * 7

Area = 56 cm²

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