Question

The base of a parallelogram is (p + 4), altitude to the base is (p - 3) and the area is (p2 - 4), find out its actual area.

Answer 1

p^2-4=(p+4)×(p-3)
=p^2-3p+4p-12
-4=-3p+4p-12
-4+12=p
p=8
area=p^2-4=8^2-4=60
Hope this was useful...

Answer 2

The actual area of the parallelogram is  "60 square units".

Step-by-step explanation:

Given,

The base of a parallelogram = (p + 4),

the altitude to the base = (p - 3) and

The area of the parallelogram $=(p^2-4)$

To find out the actual area of the parallelogram =?

We know that,

The area of the parallelogram = Base × Altitude

⇒ $(p+4)(p-3)=p^2-4$

⇒ $(p^2-3p+4p-12)=p^2-4$

⇒ $p-12=-4$

⇒ p = - 4 + 12 = 8

∴ p = 8

The base of a parallelogram = (8 + 4) = 12

the altitude to the base = (8 - 3) = 5

The actual area of the parallelogram = 12 × 5 = 60 square units

Hence, the actual area of the parallelogram is  60 square units.