Question

The base of a parallelogram is thrice it's height. If the area of the parallelogram is 972sq.cm, find the base and height of the parallelogram

Answer 1

Answer:

Step-by-step explanation:

Let the height of parallelogram=x

Base of parallelogram=3x

Area of parallelogram=972 cm^2

Base×Height=Area of parallelogram

3x×x=972

3x^2=972

x^2=324

x=18

Height=18 cm

Base=54 cm

Answer 2

Given :

• Base of parallelogram is thrice it's height.
• Area of parallelogram is 972 cm².

To Find :

• Base and height of parallelogram.

Solution :

$\longmapsto\tt{Let\:height\:be=x}$

If base of parallelogram is thrice it's height .So ,

$\longmapsto\tt{Base=3x}$

Using Formula :

$\longmapsto\tt\boxed{Area\:of\:Parallelogram=base\times{height}}$

Putting Values :

$\longmapsto\tt{972=3x\times{x}}$

$\longmapsto\tt{972={3x}^{2}}$

$\longmapsto\tt{\cancel\dfrac{972}{3}={x}^{2}}$

$\longmapsto\tt{\sqrt{324}=x}$

$\longmapsto\tt\bold{x=18\:cm}$

Therefore :

$\longmapsto\tt\bold{Height=18cm}$

$\longmapsto\tt{Base=3(18)}$

$\longmapsto\tt\bold{54cm}$

_______________________

VERIFICATION :

$\longmapsto\tt{972=base\times{height}}$

$\longmapsto\tt{972=54\times{18}}$

$\longmapsto\tt\bold{972=972}$

HENCE VERIFIED