Question

The base of a parallelogram is thrice its height. If area of the parallelogram is 432 sq. cm, then the height of the parallelogram is :​

Answer 1

Answer:

let height be x

and base be 3x

area of parallelogram= b×h

432 sq. cm= x×3x

432= 3x^2

x^2= 432/3

x^2= 144

x=√144

x=12 cm

height of parallelogram is 12 cm

Answer 2

Answer:

Height of parallelogram is $12\ cm$ .

Step-by-step explanation:

To find : height of parallelogram .

Given : base of a parallelogram is thrice its height and area of the parallelogram is  $432 \ cm ^{2}$ .

Solution:

• As per the given data we know that base of a parallelogram is thrice its height and area of the parallelogram is  $432 \ cm ^{2}$ .
• Let height of parallelogram be $x$ and base be $3x$ .  
• To find base and height of parallelogram we use formula of area of parallelogram.
• Area of parallelogram = $base \times height$

        $432 = 3x \times x\\\\432 = 3x^{2} \\\\ x^{2} = \frac{ 432}{3}\\\\ x^{2} = 144\\\\ \sqrt{x^{2} } = \sqrt{144} \\\\x = 12\ cm$

• Now , height of parallelogram is $x= 12\ cm$

                  Base = $3x = 3\times 12 = 36\ cm$