Question

The base of a parallelogram is thrice its height. If the area is 897 sq cm . Find the base and height of the parallelogram.

Answer 1

To find : base and height of parallelogram .

Given : the base of a parallelogram is thrice its height and area of parallelogram is  $897$ $cm^{2}$  .

Solution :

• As per given data we know that the base of a parallelogram is thrice its height and area of parallelogram is  $897$ $cm^{2}$  .  
• Let , $x$ be the height of parallelogram and $3x$ be the base .
• To find base and height of parallelogram we use formula of area of parallelogram.
• Area of parallelogram = $base \times height$

        $897 = x\times 3x \\ 897 = 3x^{2} \\x^{2} = \frac{897}{3} \\ x^{2} = 299 \\ x = \sqrt{299}$

• Now, height = $x = \sqrt{299} \ cm$  

                 base = $3x = 3\times \sqrt{299}\ cm$

Hence , height and base of parallelogram are $\sqrt{299} \ cm$ and $3 \sqrt{299}\ cm$ respectively .