the base of a parallelogram is twice it's height. if the area of parallelogram is 512 cm square, find the base and height
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Let the height of the given parallelogram be "h" and its base be ''b".
Then, its base (b) = 2h.
By condition,
Base × Height = Area
Or, 2h × h = 512
Or, 2h² = 512
Or, h² = 512/2
Or, h² = 256
Or, h = √256 or ± 16
Now, since the height of a parallelogram cannot be negative its height will be 16 cm. Its base will correspondingly become (2×16) cm or 32 cm.
Then, its base (b) = 2h.
By condition,
Base × Height = Area
Or, 2h × h = 512
Or, 2h² = 512
Or, h² = 512/2
Or, h² = 256
Or, h = √256 or ± 16
Now, since the height of a parallelogram cannot be negative its height will be 16 cm. Its base will correspondingly become (2×16) cm or 32 cm.
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