Question

The base of a parallelogram is twIce its
height. If the area of the parallelogram is
288 cm, find its base and height.​

Answer 1

$\huge\sf\mathbb\color{black} \underline{\colorbox{white}{☯SoLuTiOn☯}}$

Step-by-step explanation:

Let height be b.

∴ Base of ||gm ( ABCD) = Base ༝ height

= 2b ༝ b = 288

= b² = 144

= b = 12cm

• ∴ Base is = 12 ༝ 2 = 24cm
• Height is = 12 cm

Answer 2

${ \large{ \sf{ \underbrace{\underline{\bigstar \:Question}}}}}$

The base of a parallelogram is $\sf\color{red}{twice}$ its height. If the area of the parallelogram is $\tt\color{orchid}{288\: cm}$

$\bold{We\: have\: to\: find\: :-}$

$\sf\color{purple}{Base\: and\:height}$

$\bold{Given\: :-}$

$\tt{Area\: of \:parallelogram}$

$\bold\color{navy}{= 288 cm²}$

$\bold{We\: know\: that:}$

$\tt{Area\: of \:a\: parallelogram}$

$base \times height$

$\bold{Let's\: do\: it \::-}$

Let the height of the parallelogram be$\sf\color{red}{x\: cm,}$ then, base = $\sf\color{red}{2x\: cm}$

$\textbf{∴ According to the question –}$

$2x\times x$$\sf{288 \:cm²}$

$\sf{2x² \: =\: 288 cm²}$

$\sf{x²\:=\: 144 \:cm²}$

$\sf{x\: =\: 12 cm}$

$\sf\color{violet}{Hence}$

height of the parallelogram would be$\bold{12 \:cm.}$

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Thankyou :)