Math, asked by ayush86138, 1 year ago

the base of a parallelogram shape field is 250 m and its side is 200 m find the cost of watering the field at the rate 10 paise (1 rupee =100 paise) per square metre

Answers

Answered by janhvisingh56
16
&lt;b&gt;&lt;font color ="pink "&gt;<br />base of llgm = 250m<br />height of llgm = 200m<br />area = base * height&lt;br&gt;<br />200* 250
=50000 {m}^{2}
cost of watering field per m =10paise
cost of watering field 50000m=50000*10
=500000
convert into rupees =
 \frac{500000}{100}
=5000
Answered by dhritikumari524
0

Answer:

.

Step-by-step explanation:

Area of a parallelogram = (base × height) square unit.

base= 200m height= 250m

so, 200 × 250m

= 50000m²

cost of watering field per metre = 10 paise

cost of watering field in 50000m = 5000×10

= 500000

Convert into rupees...

1 rupee = 100 paise (given in question)

500000= 500000÷ 100

= RS 5000

Hence, cost of watering the field at rate of 10 rupees per metre = ₹ 5000.

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