Question

The base of a rectangular tank measures 100cm by 80cm.water is poured in the tank to a height of 50 cm. determine ,a) the pressure exerted by the water on the base of the tank
b) the force acting on the base of the tank .(take g=10m/s^2)
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Answer 1

Answer:

Given that,

density of water (ρ)=10

3

Kg/m

3

water fixed up till height (h)=2 m

Area of base (A)=100 m

2

.

assuming atmospheric pressure (P

0

)=1 atm≃10

5

Pa

so, pressure at bottom of tank,

P=P

0

+ρgh.

=10

5

+10

3

×10×2[g=10 m/s

2

]

P=(1.2×10

5

) Pa

Thus, thrust on bottom surface,

F=P.A=(1.2×10

5

)×10

2

⇒F=1.2×10

7

N

Answer 2

Answer:

Explanation:

The base of a rectangular tank measure 100cm. By 80cm water is poured in the tank to a height of 50cm determine