The base of a rectangular vessel measures 10×18cm.Water is poured into a depth of 4 cm.What is the pressure on the base?
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Answer:
pressure = 40kg/m^2
thrust = 0.72 kg
Explanation:
pressure = density×depth
= (1000kg/m^3) × (4/100)m
= 40kg/m^2
thrust of force = pressure × area
= (40kg/m^2) × (10/100) × (18/100)
= (400×18) (10000)
= 72/100= 0.27kg
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