Science, asked by hooriarukh, 4 months ago

The base of a rectangular vessel measures 10×18cm.Water is poured into a depth of 4 cm.What is the pressure on the base?
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Answers

Answered by jaspreetkaurjass
2

Answer:

pressure = 40kg/m^2

thrust = 0.72 kg

Explanation:

pressure = density×depth

= (1000kg/m^3) × (4/100)m

= 40kg/m^2

thrust of force = pressure × area

= (40kg/m^2) × (10/100) × (18/100)

= (400×18) (10000)

= 72/100= 0.27kg

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