Question

The base of a right angle is 6 cm and hypotenuse is 10 cm, it's area is

Answer 1

Using Pythagoras Theorem, c^2=a^2 + b^2
we have c=10 and a= 6
b^2= c^2 - a^2
b^2 = 10^2 - 6^2
b^2 = 100-36=64
b=8
Area of triangle = 1/2 * base * height
= 1/2 * 6* 8
=24

Answer 2

b =6m       hyp =10cm        a= ?

in this case, we can formulate using pythagoras theorem first to have the other side
a² + b² = c²
c(hypotenuse)
process =>
6² + b² = 10²
36 +b²=100
b²=100-36
b²=64
b=√64
b=8cm

area of a triangle = 1/2 * a *b
                            = 0.5 * 6 *8
                            =3*8
                            =24cm²