the base of a right angle triangle exists height by 10cm.if area of that right angle triangle is 600cm^2 find it's perimeter
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Let the altitude BC of right-angled triangle ABC be x cm. Then,
Base = BC = (x+10) cm
Area = 1/2(x+10)x. cm²
1/2x(x+10)=600
x²+10x=1200
x²+10x-1200=0
x² +40x−30x−1200=0
x(x+40)−30(x+40)=0
(x+40)(x−30)=0
x=30,−40
Hence, Base = 40 cm and Altitude = 30 cm.
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