Question

The base of a right angle triangle measure 48 cm and its hypotenuse measure 50 cm find the area of the triangle

Answer 1

Answer:

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Answer 2

Given that,

• Base of right angle triangle is 48 cm and it's Hypotenuse is 50 cm long.

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$\underline{\bigstar\:\boldsymbol{Using\: Pythagoras \ theorem\::}}$⠀⠀⠀

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$\star\;\boxed{\sf{\pink{(Hypotenuse)^2 = (perpendicular)^2 + (Base)^2}}}$⠀

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$:\implies\sf (50)^2 = (48)^2 + (H)^2 \\\\\\:\implies\sf 2500 = 2304 + H^2 \\\\\\:\implies\sf 196 = H^2\\\\\\:\implies\sf H = \sqrt{196}\\\\\\:\implies{\underline{\boxed{\sf{\pink{H = 14 \: cm}}}}}\:\bigstar$

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$\therefore\:{\underline{\sf{Hence, \ height \: of \ \triangle \ is \ \bf{ \ 14 \ cm}.}}}$⠀⠀

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FINDING AREA :

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$\star\:\boxed{\sf{\purple{Area = \dfrac{1}{2} = Height \times Base}}}$

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$\dag\;{\underline{\frak{Substituting \ values \ in \ the \ formula,}}}$⠀

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$:\implies\sf Area = \dfrac{1}{\cancel{\: 2}} = 14 \times \cancel{48} \\\\\\:\implies\sf Area = 14 \times 24 \\\\\\:\implies{\underline{\boxed{\frak{\blue{ Area = 336\:cm^2}}}}}\:\bigstar$

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$\therefore\:{\underline{\sf{Hence, \ area \: of \ \triangle \ is \ \bf{ \ 336 \ cm^2}.}}}$⠀⠀