Math, asked by rkataria758, 10 months ago

The base of a right angled pyramid is an equilateral triangle, each side of which is 6√3 cm long and height is 4 cm. Find the total surface area of the pyramid in cm².

Answers

Answered by kajusona
0

Answer:

tan30°=33l;l=3

Slant height h=32+42=5

Area of one triangle face =21×63×5

=153

Lateral S.A =3×153

=453 cm2

Area of base =43a2⇒43×(63)2=273

Total area =453+273=723 cm2

Step-by-step explanation:

hope u can understand

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