The base of a right angled pyramid is an equilateral triangle, each side of which is 6√3 cm long and height is 4 cm. Find the total surface area of the pyramid in cm².
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Answer:
tan30°=33l;l=3
Slant height h=32+42=5
Area of one triangle face =21×63×5
=153
Lateral S.A =3×153
=453 cm2
Area of base =43a2⇒43×(63)2=273
Total area =453+273=723 cm2
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