the base of a right angled traingle is 4cm and the hypotenuse is 5 c long find the area of a triangle
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b=4cm
h=5cm
a=1/2×b×ht=?
using pytjagorus theorem
Ht^2+b^2=hy^2
=>ht=_/h^2-b^2
=_/25-16=_/9=3cm
area =1/2×b×ht=1/2×4×3=6cm^2.
h=5cm
a=1/2×b×ht=?
using pytjagorus theorem
Ht^2+b^2=hy^2
=>ht=_/h^2-b^2
=_/25-16=_/9=3cm
area =1/2×b×ht=1/2×4×3=6cm^2.
homevibhag:
what is this? i can not understand
sorry
i understand
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