Question

the base of a right angled triangle is 11cm and hypotenuse is 61 cm find its area​

Answer 1

Answer:

hope this answer help dear

Answer 2

Given :-

Base = 11

Hypotenuse = 61

To Find :-

Area

Solution :-

We know that

$\bf H^2=P^2+B^2$

$\sf (61)^2 = P^2 + (11)^2$

$\sf 3721 = P^2 + 121$

$\sf P^2 =3721-121$

$\sf P^2 = 3600$

$\sf P = 60$

Now

$\bf Area = \dfrac{Base \times Height}{2}$

$\sf Area = \dfrac{60\times11}{2}$

$\sf Area = 30\times 11$

$\sf Area = 330 \; cm^2$