Question

The base of a right-angled triangle is 8 cm and hypotenuse is 17 cm . Find its the area​

Answer 1

Answer :-

( refer to the attachment )

Given :-

• BC = 8 cm
• AC = 17 cm

To Find :-

• Area of traingle

Solution :-

We know that,

Area of right angle triangle = ½ × AB × BC

Here, we are given BC, So to find area we first need to find AB

By applying Pythagoras theorem -

$\sf (AB)^2 + (BC)^2 = (AC)^2$

$\sf (AB)^2 + 8^2 = 17^2$

$\sf AB^2 + 64 = 289$

$\sf AB^2 = 289 - 64$

$\sf AB^2 = 225$

$\sf AB = 15$

So, now we have,

AB = 15 cm and BC = 8 cm

$\sf Area = \frac{1}{2} \times 15 \times 8$

$\sf = 15 \times 4$

$\sf = 60$

$\boxed{\sf Area\: of\: triangle = 60\: cm^2 }$

Answer 2

Answer:

your answer may be 60cm sq.

Step-by-step explanation:

hope it helps....♥️♥️♥️thanks please♥️♥️♥️