Question

The base of a right angled triangle is 8cm and hypotenuse is 17cm. Find its area.

Answer 1

Given:-

☆Base of right-angled triangle=8cm

☆Hypotenuse of the right-angled triangle=17cm

To find:-

☆Area of the triangle

Solution:-

According to 'Pythagoras Theorem',we know that:-

=>H²=B²+P²

Where:-

•H is hypotenuse of the triangle

•B is base of the triangle

•P is perpendicular of the triangle

=>H²=B²+P²

=>(17)²=(8)²+P²

=>P²=289-64

=>P²=225

=>P=15cm

Thus,perpendicular/height of the triangle is 15cm.

Now,we know that area of a triangle is:-

=>1/2×base×height

=>1/2×8×15

=>4×15

=>60cm²

Thus,area of the right-angled triangle is 60cm².

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Answer 2

Step-by-step explanation:

Given:-

• ☆Base of right-angled triangle=8cm

• ☆Hypotenuse of the right-angled triangle=17cm

To find:-

☆Area of the triangle

Solution:-

• According to 'Pythagoras Theorem',we know that:-

=>H²=B²+P²

Where:-

•H is hypotenuse of the triangle

•B is base of the triangle

•P is perpendicular of the triangle

=>H²=B²+P²

=>(17)²=(8)²+P²

=>P²=289-64

=>P²=225

=>P=15cm

• Thus,perpendicular/height of the triangle is 15cm.

Now,we know that area of a triangle is:-

=>1/2×base×height

=>1/2×8×15

=>4×15

=>60cm²

Thus,area of the right-angled triangle is 60cm².

________________________________

hope this helps you!!