Question

The base of a right pyramid is a square with side 10cm. height of the pyramid is 12 cm, then it lateral
surface area is
sq cm.​

Answer 1

Answer:

360cm2

Step-by-step explanation:

Area of base =10×10=100cm2=10×10=100cm2

Area of 4 Phase

=(12×Base×slant height)×4=(12×Base×slant height)×4

⇒(12×10×13)×4⇒(12×10×13)×4

=64×4=260=64×4=260

[Slant height = 122+52−−−−−−−√=169−−−√=13122+52=169=13]

Total Surface area

⇒260+100⇒260+100

⇒360cm2

Answer 2

Answer:

360cm2

Step-by-step explanation:

I hope that my answer is right